Can it be?

Often people who don't know how to add fractions do so as if the rule is $$\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}$$ where $a$ and $b$ are coprime and $c$ and $d$ are coprime. Does this ever give the right answer?

As Andrei Lazanu from Tudor Vianu National College, Bucharest, Romania says "The only solution for the problem is $a = -c$ and $b = d$ so that the sum $$\frac{a}{b}+\frac{c}{d}$$ is zero and $$\frac{a+c}{b+d}=0,$$ so the relation is true".

Why is this the only possibility? The relation

$$\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}$$ holds if and only if $$\frac{ad+bc}{bd}=\frac{a+c}{b+d}$$ that is $$(ad+bc)(b+d)=(a+c)bd$$ which holds if and only if $$a{d}^2+b^{2}c=0,$$ or equivalently $$a{d}^2=-b^{2}c.$$ We know that any whole number can be written as the unique product of prime factors. As $a$ and $b$ are coprime and $c$ and $d$ are coprime $ad^2=-b^2c$ is true only if $a$ divides $c$ and $c$ divides $a$ and they are of opposite sign, that is $a = -c$. Thus the original formula holds if and only if $d = \pm b$ and $b+d \neq 0$ that is $b=d$ so the formula holds if and only if ${a\over b} = {-c\over d}$ and their sum is zero.