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Consecutive Numbers

An investigation involving adding and subtracting sets of consecutive numbers. Lots to find out, lots to explore.

Roll These Dice

Roll two red dice and a green dice. Add the two numbers on the red dice and take away the number on the green. What are all the different possible answers?

Domino Square

Use the 'double-3 down' dominoes to make a square so that each side has eight dots.

4 Dom

Age 5 to 16
Challenge Level

We had many solutions come in for this task, thank you.  We have included some below that also wrote about how they found their answer. All of these found this solution:


Students from Wiripaang Public School in Australia sent in their thoughts and three pictures:

On Wednesday we tried to work out what number the sides of the domino square added up to. We found out it couldn't be 10 or 9 because they were too small. When some of the sides got smaller the other sides got bigger. It couldn't be 14, 15 or 16 because they are too big. When these sides got bigger the others got smaller and it wouldn't work because they weren't even. We thought it might be 11, 12 or 13.

On Thursday we started talking about our superpowers to help us uncover the mystery number. We were working in groups and we decided to use Jakai's superpower to make a plan. We used a number line and started to cross out the numbers it couldn't be. We decided that we couldn't put 6 and 6 together because it made 12 and when we added another number it made it too big. We know that 6 and 4 are friends often so we would need to put a small number next to it. We started to twist and turn the dominoes until we found that the best number would be 12. Then we keep swapping and twisting until we had 12 on all sides and the sides were even.


Green Maths group from St Joseph's Corinda in Australia wrote:

We started by laying out all the dominoes in the right pattern. We could see that one of the dominoes had dots that added to 10, so the number of dots each side had to be greater than 10.
We then attempted some trial and error (or trial and improvement as we like to call it at NRICH!). Twelve dots on each side quickly became a focus for us, because we could see how easily 12 could be made with the dots given.
By moving the dominoes around in a variety of ways we quickly found our solution.

Brandon from Coten End School wrote

I started out with the domino that has the highest value (6+4=10) at the right side and added a 1 to make a total of 11, which was our target number.  The domino with the 1 also had a number of 5 which makes a total of 6, so 11-6=5. But then we realised there was no domino with a 5, so we needed to start again. This time we still used the domino with a total of 10  (6+4=10), but now added a 2 which made our new total number of 12. The domino with the 2 also had a number of 6, which makes a total of 8. So 12-8=4. There was a domino with a 4 and 3 that makes 7, so 12-7=5. Then I used the remaining domino that had a 5 and 1 to complete the square. This meant the last side had 5+1+6=12. So all sides equal 12.

Nico from Linlithgow Academy in Scotland said:

Because there is a piece with both a six and a four the number of dots in each side must be larger than 10. It also must be smaller than 16.
From there it is possible to use trial and error - or trial and improvement - (with a focus on rotating the dominos rather than moving them every time) to come to the correct answer.

Sam H. from Mabel I. Wilson School in the United States wrote saying:

We knew that the highest sum of three domino sides would be 17. The lowest sum of three sides would be 6. We guessed that the sum of one side of our square would be 10, but we couldn't make it work. We next tried a sum of 12. That sum worked for all four sides!

Teyonne, Amy, Rika from Riverina in New Zealand said:

The smallest number was eight and the biggest number we could make was fourteen. We found we could only make fourteen once and eight twice. So we estimated that it was between nine and thirteen. So we started to lower it down and tested each number.

We also had correct solutions from these pupils:
Daniel from St Peter's
Sittingboune; Anaswar from Koodal HSS India; Sandy from Howedell Primary School ; Alesha and Ipshita, Ethan, Ayaan, Ioana and Helena from Huntingdon Primary School; Edmund from Chadwell Primary School; Tania from Avondale Intermediate New Zealand; Chris, Parth, David and Simar from Gledenning Public School, NSW Australia; Antony from Lockyers Middle School; Zelong from St. John's Beaumont China; Jesse from Channel Christian School Tasmania; Joseph from Hallam Primary School; Tom and Tate from Yanco Public School Australia; Zach, Morgan and Zak from Ravensworth C. of E. Primary School; Will, Charllie, Alyson and Gurleen from Templeton Primary School Australia; Barn Owl Class from St John's Primary Huntingdon, Rayyan from Doha College Qatar; Cory, Dylan, Zaviour, James from the Riverina School in New Zealand

Well done all of you.