### Dividing the Field

A farmer has a field which is the shape of a trapezium as illustrated below. To increase his profits he wishes to grow two different crops. To do this he would like to divide the field into two trapeziums each of equal area. How could he do this?

### Two Circles

Draw two circles, each of radius 1 unit, so that each circle goes through the centre of the other one. What is the area of the overlap?

### Star Gazing

Find the ratio of the outer shaded area to the inner area for a six pointed star and an eight pointed star.

# Ratio of Areas

##### Age 14 to 16 Short Challenge Level:

Three methods are shown below, but all of them use this idea.

If you draw lines from the centre of the hexagon to each of its vertices, 6 identical isosceles triangles are formed (with the green angles equal).

The blue angle is 360$^\circ\div$6 = 60$^\circ$, which means that the green angles must also be 60$^\circ$, and so the hexagon is split into 6 equilateral triangles - which have side length 1, the same as the hexagon.

Splitting both shapes into equilateral triangles with side length 1
We have seen that we can split the hexagon into 6 equilateral triangles with side length 1. We can try to do the same to the triangle.

Joining the midpoints of the sides, as shown on the right, we can split the triangle into 4 equilateral triangles with side length 2.

Doing the same to each of the smaller triangles formed gives equilateral triangles with side length 1. There are 4$\times$4 = 16 of these in the large equilateral triangle.

So the hexagon contains 6 equilateral triangles of side length 1, whilst the triangle contains 16. So their areas are in the ratio 6:16, which simplifies to 3:8.

Scaling the hexagon up
6 copies of the triangle will fit together to make a hexagon with side length 4.

So 6 copies of the triangle will make a copy of the hexagon which has been enlarged by a scale factor of 4.

That means its area has been enlarged by a scale factor of 4$^2$ = 16.

So 6 copies of the triangle have the same area as 16 copies of the hexagon.

So the ratio of the area of the hexagon to the area of the triangle is 6:16, which simplifies to 3:8

Scaling the triangle down
6 equilateral triangles of side length 1 fit into the hexagon. These triangles are similar to the equilateral triangle of side length 4, but their sides are 4 times shorter.

This means that their area is 4$^2$ = 16 times smaller.

So, when scaled down by a factor of 16, the area of the triangle fits 6 times into the area of the hexagon. So the area of the hexagon is $\frac6{16}=\frac38$ of the area of the triangle.

So the ratio of the area of the hexagon to the area of the triangle is $\frac38$:1, which simplifies to 3:8.

You can find more short problems, arranged by curriculum topic, in our short problems collection.