In the diagram below, all of the lines have been extended so that they cross.

b, c and the red angle form a triangle so add up to 180$^\text o$.

The same is true of f, g and the pink angle and of j, k and the orange angle.

So adding up all of the angles in all 3 triangles gives

b + c + red angle + f + g + pink angle + j + k + orange angle = 180$^\text o$ + 180$^\text o$ + 180$^\text o$

But the red angle, the pink angle and the orange angle are also the angles of a large triangle. So they also add up to 180$^\text o$.

That leaves b + c + f + g + j + k = 180$^\text o$ + 180$^\text o$ = 360$^\text o$.

Using the diagram below in the same way, l + a + d + e + h + i is also equal to 360$^\text o$.

So the sum of all of the angles denoted by letters is 360$^\text o$ + 360$^\text o$ = 720$^\text o$.

Imagine walking clockwise around the hexagon shown in red in the diagram on the right. The angles a, k, i, g, e and c are the angles that you would need to turn through to be facing in the direction of the next side.

By the time you got back to where you started from, you would be facing the same way you were facing when you started. So you would have turned through 360$^\text o$.

So a + k + i + g + e + c = 360$^\text o$.

By the time you got back to where you started from, you would be facing the same way you were facing when you started. So you would have turned through 360$^\text o$.

So a + k + i + g + e + c = 360$^\text o$.

Now imagine walking anticlockwise around the hexagon, as shown in green.

Similarly,

b + d + f + h + j + l = 360$^\text o$.

So the sum of all of the angles denoted by letters is

360$^\text o$ + 360$^\text o$ = 720$^\text o$.

Similarly,

b + d + f + h + j + l = 360$^\text o$.

So the sum of all of the angles denoted by letters is

360$^\text o$ + 360$^\text o$ = 720$^\text o$.

You can find more short problems, arranged by curriculum topic, in our short problems collection.