If Brian's age begins with 1, his father's age should end with 1

Brian's father's age won't end with 1 until Brian is more than 20

If Brian's age begins with 2, his father's age should end with 2

So their ages will be each other's reverses in 11, 22, 33... years time.

Next time is in 11 years, 14 + 11 = 25

Brian's age written $ab$, Brian's age is $10a+b$

Father's age written $ba$, Father's age is $10b+a$.

$41-14 = 27$ so Brian's father is $27$ years older than Brian.

$$\begin{align}10a+b+27&=10b+a\\

10a+27&=10b+a-b\\

10a-a+27&=10b-b\\

9a+27&=9b\\

a+3&=b\end{align}$$

$a$ | $b$ | Brian's age | Father's age |
---|---|---|---|

1 | 4 | 14 | 41 |

2 | 5 | 25 | 52 |

3 | 6 | 36 | 63 |

etc. |

You can find more short problems, arranged by curriculum topic, in our short problems collection.