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# Tennis Training

##### Age 14 to 16 ShortChallenge Level

Answer: Andy collected $16$ balls.

In terms of $a$
Suppose Andy collected $a$ balls. Then Roger collected $\frac 12 a$ and Maria collected $a-5$.

In total they collected $35$, so: \begin{align}&a + \tfrac 12 a + a - 5 = 35\\ \Rightarrow&\tfrac 52 a - 5 = 35\\ \Rightarrow&\tfrac 52 a = 40\\ \Rightarrow&a = 16\end{align}

In terms of $R$
Suppose Andy collected $A$ balls, Roger collected $R$ balls and Maria collected $M$ balls. Then $A=2R=M+5$.

In total they collected $35$ balls, so: $$A+R+M=35$$
Putting this in terms of $R$ gives: \begin{align}&2R+R+(2R-5)=35\\ \Rightarrow&5R=40\\ \Rightarrow&R=8\end{align}
Since Andy collected twice as many balls as Roger, he collected $2R=2\times8=16$ balls.

This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.