Answer: $192$, $96$, $64$ and $48$
first integer: $x$
second integer: $\frac12{x}$
third integer: $\frac13x\\$
fourth integer: $\frac14x$
$$\begin{align}x + \tfrac12x + \tfrac 13x + \tfrac 14x &= 400\\ \Rightarrow \tfrac{25}{12}x &= 400\\ \Rightarrow x &= 192\end{align}$$
Therefore the four numbers are, in order: $192$, $96$, $64$ and $48$.