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Short
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Solutions
The first large sheet of paper will hold pages 1, 2, 19 and 20; the second will hold pages 3, 4, 17 and 18; the third will hold pages 5, 6, 15 and 16.
Hence, the required sum is 37.
Alternatively, one could note that the sum of all four page numbers on one large sheet of paper is always 42. So the required sum is 42 - 5 = 37.
This problem is taken from the
UKMT Mathematical Challenges
.
You can find more short problems, arranged by curriculum topic, in our
short problems collection
.