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# Square Coordinates

Hannah tackled the first part of this problem. Here are the squares she drew:

(a)(b)(c)

(d)(e)

In all of these, the side AB could either be from the bottom corner to the right, or from the left corner to the top. Do you see why?

Hannah went on to complete the arrow notation for these squares. She's taken the side AB to be from the bottom up to the right.

(a) $A 1 \rightarrow +1 \uparrow B 1 \leftarrow + 1 \uparrow C 1 \leftarrow + 1 \downarrow D 1 \rightarrow + 1 \downarrow A$

(b) $A 2 \rightarrow + 1 \uparrow B 1 \leftarrow + 2 \uparrow C 2 \leftarrow + 1 \downarrow D 1 \rightarrow + 2 \downarrow A$

(c) $A 3 \rightarrow + 1 \uparrow B 1 \leftarrow + 3 \uparrow C 3 \leftarrow + 1 \downarrow D 1 \rightarrow + 3 \downarrow A$

(d) $A 2 \rightarrow + 2 \uparrow B 2 \leftarrow + 2 \uparrow C 2 \leftarrow + 2 \downarrow D 2 \rightarrow + 2 \downarrow A$

(e) $A 3 \rightarrow + 2 \uparrow B 2 \leftarrow + 3 \uparrow C 3 \leftarrow + 2 \downarrow D 2 \rightarrow + 3 \downarrow A$

Suppose you're given the side $A a \rightarrow + b \uparrow B$. (I noticed that $\downarrow$ could be written as $-\uparrow$ and $\leftarrow$ could be written as $-\rightarrow$, so $a$ and $b$ could be negative, but that doesn't matter. This makes it a bit easier, as we only have two sorts of arrow then.) Then the square is either $$A a \rightarrow + b \uparrow B -b \rightarrow +a \uparrow C -a \rightarrow -b \uparrow D b \rightarrow -a \uparrow A$$ or $$A a \rightarrow + b \uparrow B b \rightarrow -a \uparrow C -a \rightarrow - b \uparrow D -b \rightarrow + a \uparrow A.$$

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Hannah tackled the first part of this problem. Here are the squares she drew:

(a)(b)(c)

(d)(e)

In all of these, the side AB could either be from the bottom corner to the right, or from the left corner to the top. Do you see why?

Hannah went on to complete the arrow notation for these squares. She's taken the side AB to be from the bottom up to the right.

(a) $A 1 \rightarrow +1 \uparrow B 1 \leftarrow + 1 \uparrow C 1 \leftarrow + 1 \downarrow D 1 \rightarrow + 1 \downarrow A$

(b) $A 2 \rightarrow + 1 \uparrow B 1 \leftarrow + 2 \uparrow C 2 \leftarrow + 1 \downarrow D 1 \rightarrow + 2 \downarrow A$

(c) $A 3 \rightarrow + 1 \uparrow B 1 \leftarrow + 3 \uparrow C 3 \leftarrow + 1 \downarrow D 1 \rightarrow + 3 \downarrow A$

(d) $A 2 \rightarrow + 2 \uparrow B 2 \leftarrow + 2 \uparrow C 2 \leftarrow + 2 \downarrow D 2 \rightarrow + 2 \downarrow A$

(e) $A 3 \rightarrow + 2 \uparrow B 2 \leftarrow + 3 \uparrow C 3 \leftarrow + 2 \downarrow D 2 \rightarrow + 3 \downarrow A$

Good work, Hannah!

Ahmed gave us instructions to construct a
square where you are given one of its sides:

Suppose you're given the side $A a \rightarrow + b \uparrow B$. (I noticed that $\downarrow$ could be written as $-\uparrow$ and $\leftarrow$ could be written as $-\rightarrow$, so $a$ and $b$ could be negative, but that doesn't matter. This makes it a bit easier, as we only have two sorts of arrow then.) Then the square is either $$A a \rightarrow + b \uparrow B -b \rightarrow +a \uparrow C -a \rightarrow -b \uparrow D b \rightarrow -a \uparrow A$$ or $$A a \rightarrow + b \uparrow B b \rightarrow -a \uparrow C -a \rightarrow - b \uparrow D -b \rightarrow + a \uparrow A.$$

Well done, Ahmed, especially for spotting
that there are two possible squares.

Ahmed then worked out which of the collections of points could
be a square.

- (8,3), (7,8), (2,7), (3,2). In arrow notation, this would be $A -1 \rightarrow +5 \uparrow B -5 \rightarrow - 1 \uparrow C 1 \rightarrow - 5 \uparrow D 5 \rightarrow + 1 \uparrow A$. This is of the first form, with $a=-1$ and $b=5$. So this is a square.
- (3,3), (7,4), (8,8), (4,7). In arrow notation, this would be $A 4 \rightarrow + 1 \uparrow B 1 \rightarrow + 4 \uparrow C -4 \rightarrow - 1 \uparrow D -1 \rightarrow - 4 \uparrow D$. This isn't of either form, so the points don't form a square.
- (16,19), (18,22), (21,20), (19,17). In arrow notation, this would be $A 2 \rightarrow + 3 \uparrow B 3 \rightarrow - 2 \uparrow C -2 \rightarrow - 3 \uparrow D -3 \rightarrow + 2 \uparrow A$. This is of the second form, with $a=2$ and $b=3$, so the points form a square.
- (4,20), (21,19), (20,2), (3,3). In arrow notation, this would be $A 17 \rightarrow - 1 \uparrow B -1 \rightarrow - 17 \uparrow C -17 \rightarrow + 1\uparrow D 1 \rightarrow + 17\uparrow A$. This is also of the second form, with $a=17$ and $b=-1$, so the points form a square.

Can you work out the area of the inner square and give an explanation of how you did it?

With one cut a piece of card 16 cm by 9 cm can be made into two pieces which can be rearranged to form a square 12 cm by 12 cm. Explain how this can be done.