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Adding All Nine

Make a set of numbers that use all the digits from 1 to 9, once and once only. Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? Now try some other possibilities for yourself!

Counting Factors

Is there an efficient way to work out how many factors a large number has?

Repeaters

Choose any 3 digits and make a 6 digit number by repeating the 3 digits in the same order (e.g. 594594). Explain why whatever digits you choose the number will always be divisible by 7, 11 and 13.

Dozens

Age 7 to 14
Challenge Level

You may find the article on Divisibility Tests helpful.

Do you know a quick way to check if a number is a multiple of 2? How about 3, 4, 5..., 12..., 15..., 25...?
 
To start with, the interactivity below will generate two random digits.
Your task is to find the largest possible three-digit number which uses the computer's digits, and one of your own, to make a multiple of 2.

Can you decribe a strategy that ensures your first 'guess' is always correct?

Clicking on the purple cog gives you a chance to change the settings.
You can vary the challenge level by changing:

  • the multiple
  • the number of digits in your target number
  • the number of digits provided by the computer.

To ensure you have some choice, make sure the number of digits provided by the computer is fewer than the number of digits in the target number.

Can you describe your strategies that ensure your first 'guess' is always correct for a variety of settings?
 

Something else to think about:
 
What is the largest possible five-digit number divisible by 12 that you can make from the digits 1, 3, 4, 5 and one more digit? 

Once you've had a chance to think about this, click below to check.

Many people think the largest possible five-digit number is 53184, but there are larger ones...



Click here for a poster of this problem.


We are very grateful to the Heilbronn Institute for Mathematical Research for their generous support for the development of this resource.