Several students from West Flegg worked on this one by drawing . We apologise to those who were annoyed because the number 10 did not seem to come into the solution.
The triangle inequality states: "the length of one side of a triangle is always less than the sum of the lengths of the other two sides of the triangle". Draw a diagram and convince yourself that this has to be true.
So, using the triangle inequality, AB < AP + PB = 3 + 4 = 7 .
As triangle ABC is equilateral we also know now that CA < 7 and CB < 7. Now applying the triangle inequality to triangle CAP, and using the fact that CA < 7, gives CP < CA + AP < 7 + 3 = 10.
This shows that CP is less than 10 cm but it is obviously quite a lot less than 10 cm.
To get a better estimate, draw a circle, centre C, radius 7 centimetres, then since CA and CB are both less than 7 centimetres the whole of triangle ABC is inside the circle. As point P is inside triangle ABC it must be inside the circle and hence CP < 7 cm.