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Pair Products

Stage: 4 Challenge Level: Challenge Level:1

Choose four consecutive whole numbers.

Multiply the first and last numbers together.

Multiply the middle pair together.

Choose several different sets of four consecutive whole numbers and do the same.

What do you notice?

Can you explain what you have noticed? Will it always happen?


 

Click below to see how Charlie and Alison explained what they noticed.

Charlie said:
 

I noticed that the product of the outer pair was always $2$ less than the product of the inner pair.

I can explain this by labelling the four consecutive numbers $n, n+1, n+2, n+3$.

Outer pair: $n(n+3) = n^2 + 3n$

Inner pair: $(n+1)(n+2) = n^2 + 3n + 2$

Alison said:
 

I drew a diagram, in which the product of each pair is represented by the area of a rectangle:

The outer pair is represented by the red rectangle.

The inner pair is represented by the blue rectangle.

The purple area is common to both.

The area of the red strip will always be two units less than the area of the blue strip.

Therefore, the product of the outer pair is always two less than the product of the inner pair.


 

Instead of doing lots of calculations, can you use these representations to compare the product of the first and last numbers with the product of the second and penultimate numbers, when you have:
 

  • $5$ consecutive whole numbers
     
  • $6, 7, 8, \ldots x$ consecutive whole numbers
     
  • $4$ consecutive even numbers
     
  • $4$ consecutive odd numbers
     
  • $5, 6, 7, 8, \ldots x$ consecutive even or odd numbers
     
  • $4$ consecutive multiples of $3, 4, 5 \ldots $
  • $1.2, 2.2, 3.2, 4.2$
     
  • $2, 5, 8, 11$
     
  • $4, 4\frac{1}{2}, 5, 5\frac{1}{2}$
     

Make up a few similar questions of your own. Impress your friends by giving them a calculator and 'predicting' what will happen!
 

Click here for a poster of this problem.