Copyright © University of Cambridge. All rights reserved.

'Weekly Problem 17 - 2011' printed from http://nrich.maths.org/

Show menu


After every two numbers, one is omitted. Because $89 = 2\times 44 +1$, there must be $44$ page numbers missing and so the number on the last page is $89+44=133$.
 
 
 

This problem is taken from the UKMT Mathematical Challenges.

View the previous week's solution