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## 'Clapping Times' printed from http://nrich.maths.org/

Sam from Hitchin Boys' School, wrote in with a
general solution to this problem:

My solution is that all the numbers that are a factor of neither of
the numbers you use will be quietest.

The numbers that are factors of either
but not both will be the middle volume and the numbers that are
factors of both will be loudest.

That's very clearly put,
thank you Sam.