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Reflection in two parallel
axes gives a translation Reflection in line A maps foot 1 to foot 2. Reflection in line B maps foot 2 to foot 3. The combination of these 2 reflections is a translation perpendicular to the mirror lines by twice the distance between the two mirror lines. Reflection in two intersecting axes gives a rotation Reflection in line D maps foot 4 to foot 5. Reflection in line C maps foot 5 to foot 6. The combination of these 2 reflections is a rotation about the point of intersection of the two mirror lines by twice the angle between the mirror lines. |
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Consider the three reflections in the order they are given,
performed on the foot shape at the far left. These three
reflections give a glide
reflection
First the reflection $\alpha (z) = -\bar z$ maps $z = x + iy$
to $-(x-iy)=-x + iy$. This gives a reflection in the imaginary axis
$x = 0$ resulting in a foot going toe-to-toe with the original,
above the x-axis, with big toe near the origin, but pointing back
in the opposite $(-x)$ direction.
Now perform the reflection in the axis $x = 1$ given by $\beta
(z) = 2 - \bar{z}$ so that we have $\beta\alpha(z)$ maps $z = x +
iy$ to $-x + iy$ then to $2 - (-x - iy) = 2 + x + iy$. This gives a
foot pointing in the same direction as our original and immediately
in front of it.
Now do the reflection in the axis y = 0 given by $\gamma (z) =
\bar z$ so that the three reflections map $z = x + iy$ to $-x + iy$
then to $2 + x + iy$ then to $2 + x - iy.$ You end with a foot
below the x-axis, pointing in the same direction as the original,
with heel 2 units immediately in front of the toe of the original
giving a combination of translation and reflection known as a glide
reflection.
Repeating the reflections with the big toe of the new foot
becoming the new origin each time gives the sequence of alternating
feet walking left-to-right.
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Published May 2006.