Why do this problem?
This
problem looks like a number task, possibly revision about
multiples, but it becomes a question about establishing why
something can never happen, and creating a real proof of this. When
it comes, the proof often feels powerful, satisfying and complete,
and students leave feeling they have achieved something.
Possible approach
Ask students for a set of five numbers and then choose three
that add up to a multiple of $3$. Make a note of what they add up
to. Repeat several times. Write all the sets of five numbers on the
board clearly, with the three (that make the multiple of three)
circled, or marked clearly.
Don't say anything - let students work out what is special
about the sum of the numbers you select. Suggest that if they know
what is going on they may like to choose $5$ numbers that stop you
achieving your aim. At some stage check that they all know what is
going on.
Challenge them to offer five numbers that make it impossible for
you to choose three that add up to a multiple of $3$. Allow them
time to work on the problem, and suggest that they write any sets
they find up on the board. Students may enjoy spotting errors among
the solutions on the board.
Allow negative numbers, as long as they will allow you negative
multiples of $3$ (and zero).
At some stage there may be mutterings that it's impossible. A
possible response might be:
"Well if you think it's impossible, there must be a reason. If you
can find a reason then we'll be sure."
Once they have had sufficient thinking time, bring the class
together to share ideas.
You may need to prompt them by talking about multiples:
All numbers fall into one of these 3 categories:
type A (ie multiple of $3$)
XX...XXXXXXXX
XX...XXXXXXXX
XX...XXXXXXXX
type B (ie of the form $3n+1$)
XX...XX
X
XX...XX
XX...XX
type C (ie of the form $3n+2$)
XX...XXXX
X
XX...XXXX
X
XX...XXXX
We have found that trying to use
algebraic expressions as above, is tricky, students often end up
with n having two or more values at once. Students are unlikely to
know the notation of modular arithmetic, but the crosses notation
above is sufficient for the context, and it suggests a geometrical
image that students can use in explaining their ideas.
Ask students which combinations of As Bs and Cs would add to a
multiple of three. For each suggestion,(e.g. A+A+A, A+B+C,
B+B+B...) ask students to return to the list of numbers that were
offered earlier and find all the examples of each case.
Ask students to continue until they have found all the possible
combinations of A, B and C that sum to a multiple of $3$. Ask them
to find five numbers that don't satisfy any of these
combinations."
Soon they should realise that this will be impossible!
Ask them to set down the logic of the argument in order, like a
mathematical proof, trying to be as clear as possible each time,
and to state clearly what they have proved.
Key questions
Which types of numbers always add up to a multiple of three?
Possible extension
You can guarantee being able to get an even number when you
select $2$ from $3$ (check).
You can guarantee being able to get a multiple of $3$ when you
select $3$ from $5$.
Can you guarantee being able to get a multiple of $4$ when you
select $4$ from $7$?
Possible support
Perhaps a good idea to start by having a go at
Make 37
Multiples of $2$ added together make other multiples of
$2$.
What other numbers can we add to make multiples of $2$?
Why?
Multiples of $3$ added together make other multiples of
$3$.
What other numbers can we add to make multiples of $3$?
Why?