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Make a set of numbers that use all the digits from 1 to 9, once and once only. Add them up. The result is divisible by 9. Add each of the digits in the new number. What is their sum? Now try some other possibilities for yourself!

Legs Eleven

Take any four digit number. Move the first digit to the 'back of the queue' and move the rest along. Now add your two numbers. What properties do your answers always have?

The Genie in the Jar

Why do this problem?

This problem requires both clear thinking and the use of prime factors. It does not require much knowledge of volume and capacity.

Key questions

What are the factors of $595$?
What is its most obvious factor?
Why not try dividing by $5$?
What are the factors of the result of doing this?
Why not call the "numbers" g, o and v?
Does the problem ask which number is which?

Possible extension

Learners could go on to Stars for more work on factors.

Possible support

Suggest doing Three Spinners which is a simpler problem involving factors.