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Paper - solution


Let the sheet of paper have length x and width y. Then the uncovered area consists of two congruent rectangles of length x-y and width y- 1 2 x. So the uncovered area is 2(x-y)(y- 1 2 x), that is, (x-y)(2y-x).

The area covered twice is a rectangle of length y-(x-y), that is, 2y-x, and width 1 2 x-(y- 1 2 x), that is, (x-y). So the area covered twice is also (x-y)(2y-x).