All three together.

Let the radius of R's track be r and let the radius of the first semicircle of P's track be p; then the radius of the second semicircle of this track is r-p. The total length of P's track is pp+p(r-p)=pr, the same as the length of R's track. By a similar argument, the length of Q's track is also pr, so all three runners finish at the same time.