FF7 Angles of Polygons

If you have not met Logo before you might like to start at FF1.

In FF6 you considered and hopefully explored the following procedures:

TO CIRCLE :CH
REPEAT 360 [ FD :CH RT 1]
END

TO CIRC :CH :ANG
REPEAT 360 [ FD :CH RT :ANG]
END

As a consequence different sized circles and some polygons may have resulted. Did any of you manage to draw a heptagon (7- sided)? A nonagon (9-sided)? A endecagon(11- sided)? 13-gon? Etc. etc....

Imagine walking around the outside of a pentagon....as you: go forward then turn, go forward then turn, go forward then turn, go forward then turn, ... finally go forward then turn. You should be back where you started... go on try it, convince yourself. In your journey you should have turned through

360^{o}

Five times you turned through $72^{o}$ . N.B. 5 x 72 = 360.

Hence:

For a pentagon - REPEAT 5 [ FD 45 RT 360/5]

For a heptagon - REPEAT 7 [FD 45 RT 360/7]

For a nonagon - REPEAT 9 [ FD 45 RT 360/9]
polygons

See the pattern?
So why not experiment?
Go on try:
TO POLY :N
REPEAT :N [FD 45 RT 360/:N]
END

Then try:
TO POLY :N :M
REPEAT :N [FD :M RT 360/:N]
END

BACK FF6 - NEXT FF8