Joel Kammet
Posted on Saturday, 08 November, 2003 - 04:33 am:

I am to find the first partial derivatives of

f(x,y)=òxy cos(t2) dt

are they simply

fx=-2x cos(x2)

and

fy=2y cos(y2)

?

If not, please explain how to do this.

Joel Kammet
Posted on Saturday, 08 November, 2003 - 08:00 am:

That was supposed to be:
f(x,y) = LaTeX Imagecos(t2 )dt

I'm pretty confused by this.
Isn't this a composite function that calls for use of the chain rule?

I'm thinking that I have g(t) = t2 and the integral is f(g(t)) which gets evaluated at t=y and t=x, thus becoming f(g(x)) and f(g(y)), so cos(y2 ) - cos(x2 ) is df/dg and I still have to differentiate that wrt x to get LaTeX Imagef/LaTeX Imagex and wrt y to get LaTeX Imagef/LaTeX Imagey.

So,
LaTeX Imagef/LaTeX Imagex = df/dg* LaTeX Imageg/LaTeX Imagex
and
LaTeX Imagef/LaTeX Imagey = df/dg * LaTeX Imageg/LaTeX Imagex

Then,
LaTeX Imagef/LaTeX Imagex = LaTeX Image/LaTeX Imagex[cos(y2 ) - cos(x2 )] = -2xcos(x2 )
and
LaTeX Imagef/LaTeX Imagey = LaTeX Image/LaTeX Imagey[cos(y2 ) - cos(x2 )] = 2ycos(y2 )

But I'm not very confident about this. Please tell me if it's all nonsense.
Andre Rzym
Posted on Saturday, 08 November, 2003 - 08:42 am:

It's not correct, I'm afraid. Try writing f/x (partial derivative) as a limit as D® 0, and substitute the integral into the limit expression. You should see that 'most of' the integral cancels (you have the difference of two integrals which just differ by their limits), and you are then interested in evaluating an integral from x to x+D.

I'll post more later if that makes no sense.

Andre

Kerwin Hui
Posted on Saturday, 08 November, 2003 - 08:44 am:

There should not be a factor of 2x (or 2y respectively). If you write the integral in the form
LaTeX Image
for some fixed point p, the question reduces to applying the fundamental theorem of calculus, i.e.
LaTeX Image
and similar.

Kerwin
Joel Kammet
Posted on Saturday, 08 November, 2003 - 07:00 pm:

OK. I really needed to go back & think about the fundamental theorem for a while. The "difference" aspect is clear. I was just getting confused about which function I was dealing with.
i.e. LaTeX ImageLaTeX Image
vs.
LaTeX ImageLaTeX Image
and ending up with a mishmash of the two.


I've had better moments.

Thanks, both of you, for your help.