| Ben
Challenor |
There are 28 dominoes, with between 0 and 6 spots on each end. Turning a domino around does not make it a different domino. Event A occurs when the spots on a domino add up to 6. It is true for 4 dominoes. Event B occurs when the domino is a double. It is true for 7 dominoes. They are not mutually exclusive. Event A and Event B occur together on one domino (3,3). Now, are Events A and B independent? Initially I thought not, because of the above. But if event A is given, you have 4 dominos to choose from, and one of them is a double. Therefore the probability of B is still 1/4. So, even though this would not be the case with most examples, can you say that A and B are independent? Cheers Ben |
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| Tristan
Marshall |
Yes. Independence is actually a slightly strange property in many ways. Our intuitive notion that A and B are independent if ''A and B don't affect each other'' doesn't cover all the possibilities. We can fix things so that ''A and B do affect each other'', but we still have P(AÇB)=P(A)P(B), i.e. A and B are independent (this is what's happening in the above example). The only property that matters when determining independence of A and B is whether P(AÇB)=P(A) P(B), where P(AÇB) is the probability of A and B happening. |
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| Ben
Challenor |
Thanks for clearing that up! |