Two continuity questions


By Niranjan Srinivas on Saturday, May 25, 2002 - 08:23 am:

1) Let f be continuous at x0 and
f(x+y) = f(x)+ f(y) for all x,y E R. Prove that f is continuous for all x E R.

2) Suppose f is a continuous surjective function from [a,b] to [a,b].Prove that there is at least one point x in [a,b] such that f(x) = x.

I think these problems will help me a lot in finishing the sheet.

Thanks
Cheers
Niranjan.


By Michael Doré on Saturday, May 25, 2002 - 12:53 pm:

1) Fix any x in R. We will prove f is continuous at x. Well we have:

f(x') = f(x - x0 ) + f((x' - x) + x0 )

Letting x' -> x we have f((x' - x) + x0 ) -> f(x0 ) by continuity at x0 and as f(x - x0 ) is constant we get:

lim(x'-> x) f(x') = f(x - x0 ) + f(x0 ) = f(x)

so we're done. You can also do this with epsilons and deltas if that's the definition of "continuous" that you've been taught. By the way, can you see from here that the only solutions to the equation are f(x) = kx for some constant k?

2) Consider the function g(x) = f(x) - x. It suffices to show that g(x) has a root in [a,b]. To show this prove that there exists p,q with f(p) < = 0 and f(q) > = 0 then apply the intermediate value theorem.


[Editor: David later supplied more details for the proof of (2).]
By David Loeffler on Tuesday, May 28, 2002 - 10:21 am:

The result holds for functions that aren't surjective, and the proof is simpler; just consider g(a) and g(b). One is < = 0, the other is > = 0. Hence g(x) = 0 for some x by the intermediate value theorem, and we're done.