(arcsinx)/(1- x2 )1/2 dx and (arcsinhx)/(1+ x2 )1/2 dx


By Anonymous on Friday, February 9, 2001 - 12:42 am :

How would you go about integrating the following?
(arcsinx)/(1- x2 )1/2 dx

and

(arcsinhx)/(1+ x2 )1/2 dx
Thanks for your help in advance.


By Brad Rodgers (P1930) on Friday, February 9, 2001 - 01:07 am :

arcsin(x)/(1- x2 )1/2 dx
should solve fairly easily by integration by parts, the derivative of arcsin(x) is 1/(1-x2 )1/2 , if that helps.

I'm afraid I haven't had much time to think about the second one; it seems quite hard though.


By Anonymous on Friday, February 9, 2001 - 02:16 am :

Thanks for your help Brad.
I'll sleep on the problems and post what I get today, at a sane hour though! ;)


By James Lingard (Jchl2) on Friday, February 9, 2001 - 08:36 am :

I would have thought that the substitutions x = sin(t) and x = sinh(t) were an easier way of doing these integrals.

James.


By Anonymous on Friday, February 9, 2001 - 09:57 pm :

Thanks for that tip James.