I cannot solve one of the integration question in my textbook. Can you please help?
òcot4 x dx|
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Dear Herbert,
If this is the only point you get stuck at in the evaluation of
integrals then you obviously have a very good grasp of the
methods involved, and this is merely an annoying example. I
bashed away at this for 10 minutes before my good friend Rosemary
Bell (to whom I take all my really tricky problems), pointed out
the following solution:
(cot x)4 = (1-(sin x)2 )2 /(sin
x)4
= (cosec x)4 - 2(cosec x)2 + 1
(expanding)
Now, (cosec x)4 = (1 + (cot x)2 )(cosec
x)2
= (cosec x)2 + (cosec x)2 (cot
x)2
So,
(cot x)4 = (cosec x)2 *cot x)2 -
(cosec x)2 + 1
Bearing in mind that d(cot x)/dx = -(cosec x)2 , we
can now see by inspection that the integral of (cot
x)4 is:
-1/3 (cot x)3 + (cot x) + x + c
where c is an arbitrary constant (I know how pedantic A-level
maths teachers are about that).
And there you have it. I'm not sure it's terribly instructive but
it is a solution. Now go and do some interesting maths. :-)
Best wishes,
Richard.