ò2x^1/2[1+(1/x)]^1/2 dx

By Anonymous on Friday, March 9, 2001 - 12:25 pm :

I am having trouble with a way to integrate,
ò2x^1/2[1+(1/x)]^1/2 dx
Thanks

By Kerwin Hui (Kwkh2) on Friday, March 9, 2001 - 02:05 pm :

Rewrite the integral as

ò2(x+1)^1/2 dx

and the answer should come out immediately.

Kerwin

By Anonymous on Friday, March 9, 2001 - 02:11 pm :

How did you get it in that form Kerwin?

By Kerwin Hui (Kwkh2) on Friday, March 9, 2001 - 03:27 pm :

Recall the formula a^1/2 b^1/2 =(ab)^1/2 .

Kerwin