Why do they work: chain rule, product
rule, integration by parts?
By Olof Sisask (P3033)
on Wednesday,
October 25, 2000 - 12:51 pm
:
Hi,
I was wondering what the reasoning is behind the Chain rule and the
Product rule - why they work rather than how. Also, what is
integration by parts? I would really appreciate some help on this,
as I can't get ahold of any good books on the subject.
Thank you,
Olof.
By Susan Langley (Sml30)
on Wednesday,
October 25, 2000 - 01:33 pm
:
Ok, the chain rule. You start by
differentiating y in terms of x: yes, that is dy/dx. Now, consider
u, and u is a function of x, say u(x). We can differentiate u in
terms of x, thats du/dx and y in terms of u, thats dy/du.
OK, so what does that achieve? So, what is dy/dx? It's the rate of
change of y to x in terms of x. So dy/du is the rate of change of y
to u in terms of u, which, if you write u in terms of x becomes the
rate of change of y to u in terms of x. And du/dx is the rate of
change of u to x in terms of x. So isn't dy/du xdu/dx the
rate of change of y to x in terms of x, or dy/dx.
Ok that's the chain rule. I think I have a nice explanation on the
product rule and possibly integration by parts in my room. So, I'll
send you those when I get a chance to get back to the computer
rooms...
By Olof Sisask (P3033)
on Wednesday,
October 25, 2000 - 01:47 pm
:
Thanks Susan!
By Susan Langley (Sml30)
on Wednesday,
October 25, 2000 - 05:49 pm
:
... Ok, here's product rule:
Consider this diagram:
|
|
dy dx
|
= |
lim
dx® 0
|
|
(u+du)(v+dv)-uv dx
|
|
|
|
= |
lim
dx® 0
|
|
u dv+v du-du dv dx
|
|
|
|
= |
lim
dx® 0
|
|
æ ç
è
|
u |
dv dx
|
+v |
du dx
|
+du |
dv dx
|
ö ÷
ø
|
|
|
And, I need to go again - integration by parts to follow...
By Olof Sisask (P3033)
on Wednesday, October 25, 2000 - 06:39 pm
:
Thanks again Susan. Couple of
questions:
Does lim(dx ->
0) mean the limit of
as dx tends to 0?
Also, what happens to the + du(dv/dx) part?
Thanks in advance,
Olof.
By Brad Rodgers
(P1930)
on Wednesday, October 25, 2000 - 08:33
pm
:
As du tends to 0, because dv/dx is a
finite value, call it x, 0 x x=0. So it tends to 0 and
disappears. You are right about limits.
Brad
By Olof Sisask (P3033)
on Wednesday, October 25, 2000 - 09:33 pm
:
Ah I see, cheers Brad.
By Susan Langley
(Sml30)
on Thursday, October 26, 2000 - 09:50
am
:
OK, integration by parts, which uses the product rule:
|
= |
ó õ
|
x
x0
|
|
du dx
|
v dx+ |
x0
|
x
|
u |
dv dx
|
dx |
|
so
|
|
ó õ
|
x
x0
|
u |
dv dx
|
dx=u v- |
ó õ
|
x
x0
|
|
du dx
|
v dx |
|
Does that help?
Susan
By
Olof Sisask (P3033)
on Tuesday, November 7, 2000 - 04:14
pm
:
Cheers guys!
Regards,
Olof