Why do they work: chain rule, product rule, integration by parts?


By Olof Sisask (P3033) on Wednesday, October 25, 2000 - 12:51 pm :

Hi,

I was wondering what the reasoning is behind the Chain rule and the Product rule - why they work rather than how. Also, what is integration by parts? I would really appreciate some help on this, as I can't get ahold of any good books on the subject.

Thank you,
Olof.


By Susan Langley (Sml30) on Wednesday, October 25, 2000 - 01:33 pm :

Ok, the chain rule. You start by differentiating y in terms of x: yes, that is dy/dx. Now, consider u, and u is a function of x, say u(x). We can differentiate u in terms of x, thats du/dx and y in terms of u, thats dy/du.

OK, so what does that achieve? So, what is dy/dx? It's the rate of change of y to x in terms of x. So dy/du is the rate of change of y to u in terms of u, which, if you write u in terms of x becomes the rate of change of y to u in terms of x. And du/dx is the rate of change of u to x in terms of x. So isn't dy/du xdu/dx the rate of change of y to x in terms of x, or dy/dx.

Ok that's the chain rule. I think I have a nice explanation on the product rule and possibly integration by parts in my room. So, I'll send you those when I get a chance to get back to the computer rooms...


By Olof Sisask (P3033) on Wednesday, October 25, 2000 - 01:47 pm :

Thanks Susan!


By Susan Langley (Sml30) on Wednesday, October 25, 2000 - 05:49 pm :
... Ok, here's product rule:

Consider this diagram:

Diagram

y = u v

dy
dx
=
lim
dx® 0 
(u+du)(v+dv)-uv
dx

=
lim
dx® 0 
u dv+v du-du dv
dx

=
lim
dx® 0 
æ
ç
è
u dv
dx
+v du
dx
+du dv
dx
ö
÷
ø

=u dv
dx
+v du
dx
And, I need to go again - integration by parts to follow...

By Olof Sisask (P3033) on Wednesday, October 25, 2000 - 06:39 pm :

Thanks again Susan. Couple of questions:
Does lim(dx -> 0) mean the limit of as dx tends to 0?
Also, what happens to the + du(dv/dx) part?

Thanks in advance,
Olof.


By Brad Rodgers (P1930) on Wednesday, October 25, 2000 - 08:33 pm :

As du tends to 0, because dv/dx is a finite value, call it x, 0 x x=0. So it tends to 0 and disappears. You are right about limits.

Brad


By Olof Sisask (P3033) on Wednesday, October 25, 2000 - 09:33 pm :

Ah I see, cheers Brad.


By Susan Langley (Sml30) on Thursday, October 26, 2000 - 09:50 am :
OK, integration by parts, which uses the product rule:


u v= ó
õ
x

x0 
d(u v)
dx
dx

= ó
õ
x

x0 
du
dx
v dx+
x0
x

 
u dv
dx
dx
so
ó
õ
x

x0 
u dv
dx
dx=u v- ó
õ
x

x0 
du
dx
v dx
Does that help?

Susan


By Olof Sisask (P3033) on Tuesday, November 7, 2000 - 04:14 pm :

Cheers guys!

Regards,
Olof