Volumes of n-spheres
By James Foster :
Just wondering if anyone knew the general formula for the
volume of an n-sphere (that is a sphere/hypersphere in n
dimensions)
James
By James Foster :
Okay it's not perfect, but say the diagram below is that of a circle with
radius R and at any point x it has a length perpendicular to the x-axis
of 2z. Consider the following:
z = Rcos(t)
x = Rsin(t)
dx/dt = Rcos(t)
The area of the circle can be worked out by the integral of the lengths of the
lines at position x with respect to x between -R and R. This is
ò-RR 2z dz = ò-RR 2Rcos(t) dx
as x goes from -R to R, t goes from -p/2 to p/2 so
ò-RR 2Rcos(t) dx=òp/2-p/2 2Rcos(t)(dx/dt)dt =òp/2-p/2 2(r2)cos2(t) dt since cos2(t)=(cos(2t)+1)/2
area =òp/2-p/2 (R2)(cos(2t)+1) dt since sin180=0 the cos(2t) cancels and leaves area =òp/2-p/2[R2 t]=pR2
the notorious formula for a circle's area using the same notation as above. The
volume of a sphere can be worked out by the integral of the area's of its
slices at position x.
Therefore, volume =ò-RR(p) z2 dx=òp/2-p/2(p)R2 cos2(t) (dx/dt) dt
=òp/2-pi 2(p)R3 cos3(t) dt
=òp/2-p/2[(p)R3(sin(t)-sin3(t)/3)]
=(p)(R3)2(1-1/3)
=(4/3)(p)(R3) the formula for the volume of sphere
If the theory is right then we can work out the hypervolume of a 4-ball by
integrating the volume of the spherical slices.
So ò-RR (4/3)(p)z3 dx
=òp/2-p/2(4/3)(p)R3cos3(t)(dx/dt)dt =òp/2-p/2(4/3)(p)R4cos4(t) dt
since cos4(t)=cos(4t)/4+cos(2t)/2+3/8 and as before sin180=0 and sin360=0 then cos(4t) and cos(2t) integrate to 0
The hypervolume =òp/2-p/2(4/3)(p)R4(3/8)
=(1/3)(p2)(R4) Let C(n)=òp/2-p/2cosn(t) dt
C(1)=2 C(2)=(1/2)p C(3)=4/3 C(4)=(3/8)p C(5)=16/15 C(6)=(5/16)p
in general Vn(R)=R(Vn-1(R))(C(n))
The two formulas I gave can be proved using mathematical induction to be
the above.
[Ed: indecipherable image omitted here --
John if you'd like to upload a gif or jpg then please do!
]
By Wallace Home on Thursday, December
17, 1998 :
Try starting with 2p, 8p, 32p,...... integrate up to the required
dimension and see what constants must be multiplied in. ignore constants of
integration, i think (read hope). This might provide a better idea of how the
expressions for hypervolumes of hyperspheres can be generated.
I must point out (no pun intended) that 2p is not a point: it has zero
dimensions and is just a number. it doesn't do anything, it has no spatial
place in relation to r or anything else. dimensionless numbers cannot be
points. 2pPr is 1-dimensional expression, or point. (For comparison,
imagine the question "How are you today?" Answering it with "42" or any other
number is meaningless unless you give the number a dimension).
this whole thing is irritating me, actually, since everyone seems to think
that "2000" is significant. OK, it's a good excuse to have a party, but I think
people read too much into just an empty quantity. Is 2048 more significant
than 2000? why? I'd like to start a discussion about the whole meaning or
numbers thing, cos it's interesting how people perceive them.
Ed.