I have a big problem with radicals.
So what in the world is 7 sqrt 3 suppose to mean?
And how are the ways to put it back to normal?

Thanks alot!!

Okay I'll try explain the general idea...

If you have the equation x² = 4 (x is positive) the solution is simply 2
But what if you had x² = 2?
Using a calculator you get 1.41421... but this is only an approximation so it is better if you just leave the answer as sqrt 2. This is more concise and more accurate as you're not rounding off anything...

Now,
Using the fact that (ab)ⁿ = aⁿ bⁿ and noting that p^1/2 means the square root of p we can do the following:
Say we had $\sqrt{12}$
We can write this as (12)^1/2 = (3x4)^1/2
By the rule I mentioned before you can split this up...
Therefore,
(3x4)^1/2 = (3)^1/2 (4)^1/2
But $4^{1/2}=2$ and so $(3{)}^{1/2}(4{)}^{1/2}=\sqrt{3}(2)$ (or $2\sqrt{3}$, it's more common to put the rational number first)
So we have...
$\sqrt{12}=2\sqrt{3}$ ( $2\sqrt{3}$ basically just means 2 multiplied by $\sqrt{3}$)
Can you now see that $\sqrt{8}=2\sqrt{2}$ and $\sqrt{45}=3\sqrt{5}$...

So, in response to your original question:
$7\sqrt{3}$ means 7 multiplied by $\sqrt{3}$...

Can you see (by reversing the process above) why this is ?

So we can write this as:

1. $7\sqrt{3}$
2. $\sqrt{147}$
3. 12.1243556...