Hello NRich folks,
In the following question I don't have a clue of what it is
asking for. Especially when it says 'unit place' (well I have an
inkling but not certain).
Let a1 = 3, an+1 = (an
)3 for n> =1
(Thus a2 = 33 , a3
(33 )3 and so on.)
What digit appears in the unit place of a7 ?
Hal.
PS: I forgot to mention, we can't use the calculator for this
question.
Hi Kerwin.
Thanks for that.
I am sorry to say that I don't know what 1 mod 10 means? Can you
be kind enough as to briefly explain what it means.
Thanks for your help.
Hal.
A less sophisticated method of solving this problem is to
consider what determines the value of the digit in the unit place
for each member of the sequence. Try working out the unit place
for n = 1, n = 2, n = 3 &c. if you still can't see the way it
works.
Tom.
1 mod 10 means that it's in the form 10n + 1 (where n is an
integer).
/Olof
All of the numbers in the series are some of the terms in the
series 3n , where n increases. The unit place in every
number 3n is 3,9,7 or 1.
If n/4 has no remainder, then 3n =1 mod 10
if n/4 has a remainder 1, then 3n =3 mod 10
if n/4 has a remainder 2, then 3n =9 mod 10
if n/4 has a remainder 3, then 3n =7 mod 10
If you can work out a value for n in the term a7 ,
then it will be quite easy to work out the unit place. This
probably seems like quite a crude way way of working it out. The
series described in the original thread is a special case of the
above and I think you could work out a rule for that series. I
don't really see why this is the case though, do all power series
have a repeating set of unit places?
Yes, all power series have a repeating set of unit places
(although they may have a set of non-repeating unit places
previous to this - in the same way that fractions give a
repeating set following a non-repeating set).
The proof is simple:
Let an+1 = (an )k
Then un+1 is equal to the unit place of (un
)k where un is the unit place of
an .
Hence, if ua = ub then ua+1 =
ub+1 .
Since un can only take 10 different values, for some a
there exists b such that ua = ub .
Hence there is a repeating set of unit places.
Tom.
The proof is simple, but that's not it. That's the proof for
repetition in the series defined in the original question. The
proof for power series should read
Let an+1 = an ×k.
Then un+1 is equal to the unit place of un
×k where un is the unit place of
an .
Hence if ua = ub then ua+1 =
ub+1 .
Since un can only take 10 different values, for some a
there exists b such that ua = ub .
Hence there is a repeating set of unit places.
Both these proofs depend on the obvious property that the unit
place of an+1 in the series is dependent only on the
unit place of an .
Tom