Is 0 a very common multiple?
By Lesley Hale (T1446) on Saturday,
November 6, 1999 - 08:19 am :
Can anyone help me? I am confused as to whether 0 is a
multiple & indeed a common multiple of every integer. In one
of my text books it clearly shows 0 as a common multiple, but in
others it is not mentioned. If not, why not? Several people I've
asked have said 0 is not a number. In which case what is the
number between 1 and -1? I need some simple, child friendly
explanations.
By Anton Ilderton (Abi20) on Saturday,
November 6, 1999 - 08:37 am :
There was a popular-science "craze" a
little while back where people would run up to mathematicians in
the street and go "Ha! Zero is not a number! I read it in a
magazine!". Hmmmm. Suffice that 0 IS a number just as good
as 1 or -1.
As to the multiples, it's really a question of definition. For
example, 2x3=6, hence 6 is a multiple of 2. 2x10 = 20 so 20 is a
multiple of 2. So 2x0 = 0 and 0 is a multiple.
However, some people don't let you multiply by zero in their
definition of multiples, so you really have to go with which ever
definition your book is using at the time.
I wouldn't worry too much about it (unless your entire homework
sheet is based on it...), it's really not that essential!
I'm sorry if this is a little vague- perhaps some number-theorist
here can give you a clearer answer!
Anton.
By Chris Jefferson (Caj30) on Monday,
November 8, 1999 - 03:32 pm :
The simple answer to this is that you
would be suprised how many things in maths do not have a fixed
definition, and many of these definitons are involved with 0s and
1s. Is 0 a multiple? Is 1 a prime? Should a semi-positive
definitive matrix have at least one zero? (sorry, my work at the
moment..)
In these case it really is up to you to define it how you want.
The only important thing is to state which definition you are
using when you quote your result..
So either of
- 0 is a multiple, so it is very
common
and
- 0 is not a multiple, so it isn't common at all
are both as good as each other. I wouldn't try pushing what
you can redefine too far, at least until you get to
university.
Chris
By Jonathan Kirby (Pjk30) on Monday,
November 8, 1999 - 08:03 pm :
I would suggest that 0 is certainly a
multiple.
This is obvious since
0 x n = 0
for all numbers, n.
You could certainly define 0 not to be a multiple, but I don't
really see the point. (I wouldn't do it, but other people might.)
Probably the reason that some textbooks don't mention it is that
it is
"trivially" a multiple of everything so it's not really very
interesting compared with e.g. the fact that 12 is a multiple of
1, 2, 3, 4, 6 and 12, or that 13 is a multiple of 1 and 13
only.
Jonathan
By Tom Read (T1386) on Sunday, November
14, 1999 - 10:44 am :
This reminded me of my earth-shattering discovery of the
possible values of 0/0:
2 x 0 = 3 x 0
implies
0/0 = 3/2...and infinite other possibilities
An even worse one is evaluating i as zero:
Anyway, in my Maths degree at University of Newcastle
upon Tyne, Dr Dye (now Professor Dye) was convinced, and
convinced us, that 0 divides everything and everything divides
zero were good baseline definitions to use.
Tom Read
By Adam Wood (Ajpw2) on Sunday,
November 14, 1999 - 01:30 pm :
2 x 0 = 3 x 0 does not usually imply 0 /
0 = 3 / 2 since division by zero is conventionally
undefined...
By Jonathan Kirby (Pjk30) on Sunday,
November 14, 1999 - 04:25 pm :
Also: a divides b if & only if there
exists c such that
a x c = b
If a = 0 then a x c = 0 for all values of c, so 0 does not divide
anything
except itself.
Jonathan
By Michael Doré (P904) on Sunday, November 14, 1999 - 07:35pm:
I still think that 0/0 has an infinite number of values. The
definition of a / b is:
a / b = c
is equivalent to
a = b x c.
Let a = b = 0 and you have:
0 = 0 x c
which any value of c can satisfy. But c = 0/0. Therefore 0/0 is
multivalued and returns the set of complex numbers.
Michael
By Chris Jefferson (Caj30) on Sunday,
November 14, 1999 - 08:42 pm :
Just a few points to add...
saying: ''a divides b if & only if there exists c such that a
x c = b'' is simply one definition of a divides b. There is no
'fixed' one, although I will admit that is the most used
one.
Also, a / b is defined to be a x c
where c is the number such that b x c = 1
(c is called the 'inverse' of b)
When b=0, there is no c such that bc=1, so you cannot divide by
zero!
After what I said before, this is one point where the definiton
is absolute!!
I will quote you one of my favourite alternative maths.
---------------------
Alternative Maths
Axiom 1: Same as normal maths
Axiom 2: You can divide by 0
Theorem 1: all numbers a and b are such that a=b
Therefore all numbers are solutions to all equations.
END
----------------
Would make maths so much simpler don't you think?