Given Fn = 1 5 ( αn - βn ) where α and β are solutions of the quadratic equation x2 -x-1=0 and α>β show that

(1) αβ=-1, α+β=1

(2) 1 α + 1 α2 = 1 β + 1 β2 =1

(3) F1 = F2 =1 and Fn + Fn+1 = Fn+2 and hence Fn is the nth Fibonacci number and

(4) the sum 1+ F1 + F2 + Fn gives another Fibonacci number.