xn =(n+1 )2 +(n+2 )2 +[(n+1)(n+2 )]2 xn = n2 +2n+1+ n2 +4n+4+[ n2 +3n+2 ]2 = n4 +6 n3 +15 n2 +18n+9 =[ n2 +3n+3 ]2