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'Drawing Celtic Knots' printed from http://nrich.maths.org/
William from Barnton Community Primary School
If there is a rectangular Celtic knot that is M by N then the
number of ribbons is the highest common factor of M and N.
In this case M = 5 and N = 3 so the number of ribbons is 1.
Therefore, if a square Celtic knot has side length x, the number of
different ribbons will be x.
In this case x = 4 so the number of ribbons is 4.
The number of crossovers for a square Celtic knot is $$2x^2 - 2x$$
or $$2x (x - 1)$$
Students from Garden International School also worked on this
Kenn, Jong Woong, Jayme and Marana sent us.