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Methanal, ethanal, propanal and butanal form the first four compounds in a sequence of alkyl aldehydes with molecular formulae
CH$_2$O, C$_2$H$_4$O, C$_3$H$_6$O, C$_4$H$_8$O
What would be the molecular formula for pentanal and hexanal?
What would be the general formula for the $n$th molecule in the sequence? What masses could it have, taking into account these common isotopes of C, H and O:
$^{16}$O $99.76\%$, $^{17}$O $0.04\%$, $^{18}$O $0.2\%$
$^{12}$C $98.9\%$, $^{13}$C $1.1\%$
$^1$H $99.99\%$, $^2$H $0.01\%$
The relative abundance of the lightest form of one particular type of alkyl aldehyde is almost exactly $8$ times that of its next lightest form. Can you work out its molecular formula?