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Consider all of the five digit numbers which we can form using only the digits 2, 4, 6 and 8. If these numbers are arranged in ascending order, what is the 512th number?

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Double Digit

Choose two digits and arrange them to make two double-digit numbers. Now add your double-digit numbers. Now add your single digit numbers. Divide your double-digit answer by your single-digit answer. Try lots of examples. What happens? Can you explain it?

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What an Odd Fact(or)

Can you show that 1^99 + 2^99 + 3^99 + 4^99 + 5^99 is divisible by 5?

Cycle It

Age 11 to 14 Challenge Level:

Write down any nine digit number which uses each of the digits 1, 2, 3, ..., 9 once only.
Change the number by re-writing it with the very first digit as the units digit at the end and otherwise keeping the digits in the same order.

For example 354218697 becomes 542186973.

This is called a cyclic permutation of the digits. By now you will have two numbers written down.

Repeat the cyclic permutation again and again writing down all the new numbers you obtain until you get back to your first number. Add up these nine numbers.

Prove that, whatever number you chose originally, the total obtained in this way is the same.

[Note: The digits can be cyclically permuted in the opposite direction and, more generally, abcdefghi and bcdefghia are cyclic permutations of each other].