Take any pair of two digit numbers $ ab $ and $ cd $ where, without
loss of generality, $ ab> cd $. Form two 4 digit numbers $ abcd $
and $ cdab $ and calculate: \[\frac{abcd^2-cdab^2}{ab^2-cd^2}\]
Repeat this with other choices of $ab$ and $cd$. There is a common
feature of all the answers. What is it? Why does this occur?
Generalise this to $n$ digits for other values of $n$.