hi, im doing an investigation entitled 'taxicab geometry', ive
attempted it and have done most of the practical part of it. But i
cant seem to see the equation behind it all. please guide me in the
right direction.
they provide a regular grid with regular horizontal and vertical
lines. the lines are roads and the actual squares are blocks of
hoouses/ buildings.
in taxicab geometry the distance between place A & B is worked
out by adding together the horizontal and vertical distances.
each square is counted as 1 unit.
Part 1 (ive done this)
a taxicab firm is based at A. the position B is 7 units away from
A.
investigate all the positions of B at 7 units. investigate for
different distances.
i found that all the points when plotted form a diamond shape. the
same shape is formed for different amounts of units.
what formula can u get for the positions of the points? i have
already found a formula for the number of points there are.
part2
the bus station is X. the railway station is Y. the distance XY=6
units.
investigate to find where the taxicab firm could be sited, so that
the same distance from the bus station and the railway station.
What does happen if the locations of the bus and the railway
station are varied???
part 3
the taxi cab firm decides to site its office so that the distance
from the office to the bus station is twice the distance to the
railway station. Where could the office be sited? ALL the possible
positions and formulas????
Please help, i havent left it to the last minute, but i know
already i dont understand!!!
Desperatley Jack
(by the way im Yr 10 UK, (1 year before GCSE)
Hi Jack,
I think you'll find that once you have the basic idea of how to
construct and use the formula things will become clear, so we'll
start with the first part where we already know the answer.
If you're going to have a formula that tells you which points on
the grid B can be at, you're going to need to label the points on
your grid by numbers, as you are doing when you draw a graph. Now
you could start your grid with the (0,0) point anywhere and have
the point A at (4,5) for example, but thinking ahead, the problem
might be simplified if we choose A to be in a "nice" simple place,
and the nicest place on the grid is (0,0).
So the points a distance 1 from A are (1,0), (-1,0), (0,1) and
(0,-1). I hope you can see how the points on the grid are being
labelled by this example. Now we are ready to start considering a
formula. The points we are interested in are those a distance 7
away from the (0,0) point, but how can we express this
mathematically? Well how about the point (4,5)? You already know
that this is a distance 9 from (0,0) since to get to it you must go
4 across and 5 up, 4+5=9. But how about the point (-4,5)? Again you
must move 4 then 5 points, so the distance is again 9. With a bit
of thought you can see that the sign of the co-ordinates is
irrelevant, the minus signs are just ignored when we are
calculating the distance. There is a function that is used widely
in maths that allows us to write down this ignoring of the minus
sign, I'll write it as square brackets, it goes something like
[-3]=3, [3]=3, [-5]=5 etc. You get the idea.
Take now, a general point on the grid, call it (x,y) where x and y
stand for numbers. The distance of this point from (0,0) is
[x]+[y], and our problem requires that this distance be equal to 7,
giving the formula [x]+[y]=7.
It may look a bit scary at first with the square brackets but all
you have to do to find which points are a distance 7 from A is put
in a value of x and solve for y. So to find the points with x
co-ordinate 4 that are a distance 7 from x we say:
[4]+[y]=7
so [y]=7-[4]=3
so y=+3 and -3
and our points are (4,3) and (4,-3). By using different x's you can
build up a picture of the shape the points form. By the way, what
will happen if you try to find points with an x-value of more than
7, and why?
I know that you have done this part already and found the shape to
be a diamond, but the method is very powerful, and using the same
ideas you can get an equation that tells you the possible positions
of the cab company in all the questions in your project. For part
2, there are two points that you start with, so you can only put
one of them at (0,0) when you make your grid, so what will be the
distance of the general point (x,y) from the other point, if it is
(1,5) for example? Well I'll tell you the answer and see if you can
see where it came from. The distance from (x,y) to (1,5) is
[x-1]+[y-5].
You should get (roughly) straight lines of points for your answer
to part 2, but the answers to part 3 are the most interesting of
all.
I hope this has helped, as always, please tell me if you have any
queries about any of the above and I'll do my best to answer
them.
Best wishes,
Richard Dwight.
If this is a GCSE coursework, you will need to give details of the help you have had. This will not necessarily affect your mark, especially as Richard has given you hints and suggestions rather than answers.