What is the gradient of a point of inflexion of a curve? Eg: y =
x3 How do I measure it?
Also, is it that all cubic equation has a pt of inflexion?
A point of inflexion is defined as a point
on a curve where the concavity changes. To find these points we
look at the second derivative of the equation of the curve, f(x).
At the point of inflexion f''(x) (i.e.
d2y/dx2) = 0 and is changing sign. i.e.
f'''(x) ¹0 or if x0 is
the x value of the point of inflextion, then f''(x0 + a)
< 0 and f''(x0 - a) > 0 (a is a constant), or vice
versa. Therefore when you find the points of inflexion you
naturally have the x values (x0). So the gradient at the
point of inflexion here is just f'(x0), you either have
the equation for f'(x) or can find it by integrating f''(x).
Have to dash to work now - unless somebody else does the other bit,
i'll give it a stab later.
Cheers
sam
Most cubic equations don't have one single point of inflection, a typical cubic equation with positive x3 in it (and various other quantities of x2 and x and c) would have a maximum point, then a minimum point.
I would think all cubic equations have one and only one point of
inflection: y = ax3 + bx2 + cx + d implies
d2y/dx2 = 6ax + 2b, which changes from
negative to positive, or vice-versa at it's zero, which occurs at x
= -b/(3a).
Jamie's right about the local maximum and local minimum; in general
a cubic has one local max and one local min. In fact either
a) the cubic has no local max. or min, but a point of
inflection,
or
b) the cubic has a local max. and min. and also a point of
inflection, all distinct
Brad
Remember that a point of inflexion need
not be a stationary point. For example, f(x) = x3-3x has
an inflexion point at 0 (draw it) and maxima and minima at
±1.
David
So what exactly is a point of inflexion?
basically where the curve is 'straight'
like y=sinx at x=0 the line is changing concavity, with gradient 1.
Literally "inflexion" = "no curvature", neither concave nor convex.
The point also must mark a transition from concave up to concave
down (or from concave to convex, depending upon which terminology
you use). So the vertex of a quadratic is not a point of
inflection.
I think that's already been said, but I've said it again
anyways.
Brad
Hmm. I would say f(x) = x4 has
a point of inflexion at the origin despite being convex
everywhere.
David