Is it possible to construct a pyramid using scalene triangles?
Yes. I don't know which of the following
will be most helpful.
Imagine a cuboid with all three lengths different. Now imagine
slicing it through the diagonal of the base up to one of the top
corners not above that diagonal.
I'm afraid I can't draw on this computer - I've got a net in front
of me. Try following this description:
For the base, draw a right-angled triangle with the perpendicular
sides length 3 and 4. Then imagine that the vertex is 2 units above
the right-angle. The next two triangles are right-angled triangles
with perpendicular sides 4/2 and 3/2. The last triangle will need
to be constructed with compasses:it will not be right-angled, and
the side-lengths will need to match the three hypotenuses.
Sorry if that's rather garbled. If you can't follow either
description, post again, and maybe someone will provide a
diagram.
This, of course, is just one example. I suspect constructing one
with fewer right-angles will be harder.
Here's a picture. The green triangle is
what I described as the base. The fourth triangle will go on the
third side of the green triangle, and would need constructing with
compasses.