I have a logic puzzle:
A green car and a red car are 100 miles away from each other.The
green car travels at 80 miles an hour. the red car travels at 20
miles an hour. There is a bird above the green car that flies
towards the red car until it meets it, then goes back to the green
car and so on.
The bird travels at 50 miles an hour.
How far will the bird have traveled when the cars collide?
Assuming that both cars are going in the same direction, taking
this as the positive direction, and that the green car is following
the red car.
The speed of the green car with respect to the red car =
+60mph
so the time taken for the two cars to collide will be = (100/60)hrs
(since time = distance/speed)
In this time the bird would have flown a distance of =
(100)/60)×(50) (since distance = speed × time)
= 83.33 miles (4 sgf)
Sorry as the cars are going towards each other
If the cars are going towards each other, they will collide once
they have covered a distance of 100 miles between them. This occurs
after one hour, since the red car has travelled twenty miles and
the green car 80.
So, the bird will have travelled 50 miles in the hour before the
cars collide
Very good Chris!
For a famous story about von Neumann solving this problem, see http://www.primepuzzle.com/leeslightest/howfar.html