I have a couple of problems. Can you help me, PLEASE!
(just show me how to set up the integrals)
Use the method of cylindrical shells to find the volume generated
by rotating the region bounded by
1) y=x2 , y=0 , x=-2 , x=-1 about y-axis
2) y=(x-1)1/2 , y=0 , x=5 about y=3 (I know the answer
is "24 pi"; but I don't know how to set up.)
3) y=x2-3x+2; y=0 about y-axis.
I really appreciate your help!

When you have a curve as shown, you can rotate it around the y-axis
to get a solid. To find the volume, divide the solid into thin
slices (one is shown on the diagram) of width dx each. These slices are approximately cylinders
of radius f(x), and as dx®0 the approximation becomes better and better.
Therefore, if V is the volume of the solid and a & b are the
start and end x values:
V=Sb ap[f(x)]2dx
=òa bp[f(x)]2dx
=...
For the second part, first subtract 3 from y (so y=...-3) then
treat as if rotating about the y-axis.