What is the area of a hexagon with respect to one of its six
sides? Can someone prove this for me?
Thanks Louise
I assume we are dealing with a regular
hexagon (i.e. all sides the same length etc). Divide the hexagon
into six triangles, so the central corner must have an angle of 60
degrees, and the other two angles must be the same as each other,
and the total must be 180. So all angles of the triangle are 60
degrees. Can you work out how large the triangle is now? Then
multiply it by 6 for the size of the hexagon.

Take a regular hexagon with its six sides of length a.
The 6 equilateral triangles contained within this hexagon also have
all their sides equal to a.
The area of a triangle is its base (in this case a)x by its
perpendicular height (which is unknown). I thought that if i could
find the perpendicular height in terms of a by manipulating
Pythagoras' theorem then I would be able to determine the area of
the hexagon with respect to a.
Do you see what I'm rambling on about?
By using Pythagoras: let the perpendicular height be p
so;
a2=a2+p2 as sides of a equilateral
triangle have equal length don't they...
p=root(a2-a2) which doesn't make
sense...
Where am I going wrong?
Louise x
I
assume that you are considering the triangle running from half way
along one side to the opposite corner. So sides have length a, a/2
and p. Not a,a and p! So it is
a2=(a/2)2+p2.
Can you take it from there?
In a more simple way,
angle of a equilateral triangle is 60.
so sin 60 = p/a
hence p = sqrt(3) × a/2
area of the equilateral triangle
= 1/2 × p × a
= 1/2 × sqrt(3) × a/2 × a
= sqrt(3) × a2/4
hence carry on from here..
love arun
Well louise,
What does "Doh!" mean?
love arun
Do u not watch the simpsons?
Louise x aka Homer
[For other international readers, The
Simpsons is a cartoon, very popular in the USA and UK. Louise's
"Doh!" was an expression of annoyance with her own error! - The
Editor]