These two challenging questions are giving me a tough time, can
anyone help?
1) It was once claimed that there are 204 squares on an ordinary
chessboard. Can you justify this claim?
2) How many rectangles are there on a chessboard?
Thanks in advance for all of your help and explanations!
1)-
1×1 squares - 64
2×2 squares - 49
3×3 - 36
4×4 - 25
.
.
.
(can you see why this is true?)
64+49+36+...=204
A similar process of logic holds for the rectangles, and if you
organize your data right, you should see another pattern. I think
you'll get answer of 1296. I'll go ahead and let you see if you can
discover this pattern, and then I'll try and explain why it holds
true. (Hint:if you want to figure out why it holds true by
yourself, think of triangular numbers inside what is being
multiplied-that probably doesn't help much, sorry)
Brad
Any more hints or explanations?
Think about each size of rectangle in turn. You might find it helpful to use a chessboard and a piece of paper of the right size. Hopefully you can see how this table builds up:
| Rectangle size | Number of ways | |
| 1×1 | 8×8 | 64 |
| 1×2 | 8×7 | 56 |
| 1×3 | 8×6 | 48 |
| 1×4 | 8×5 | 40 |
| ... | ... | ... |
| 2×1 | 7×8 | 56 |
| 2×2 | 7×7 | 49 |
| 2×3 | 7×6 | 42 |
| ... | ... | ... |
Here's another way of thinking of it for
the rectangles one.
If we want to create a rectangle on the chessboard, what we have to
do is draw two vertical lines and two horizontal lines. 
How many ways are there of doing this?
For the first horizontal line, we have 9 choices of where to draw
it. For the second, we have eight choices left. That gives
9×8=72 combinations. But this counts each combination twice
(once with the top line chosen first, once with the top line chosen
second), so we divide by two, getting 36.
The same argument holds for the vertical lines. So overall we have
36×36=1296 possibilities.