If you look at the 1,3,7,9,and all the other odd numbered tables
but not ones that have 5 as their last digit.
Example the 3 x table upto 10 x: 3,6,9,12,15,18,21,24,27,30.
If you remove the "tens"digits you are left with the following,
3,6,9,2,5,8,1,4,7,0. You now have all the numbers upto ten. The
question is why is this so and, why does this not work for the 5x
table or any other table with 5 as the last digit as this works for
all other odd numbers?
This is a very good question and what you
say is quite right. It will work for any number that is not in the
2 or 5 times table (however far you go).
important thing here is that 2×5=10, and when you get to a
multiple of ten in the times table you are looking at, you are back
where you started: the next entry in the times table will have the
same last digit as the first one did. In fact, that is the only way
the pattern of last digits can repeat itself. If the pattern does
not repeat itself in the first ten entries of the times table, then
all the last digits must be different and you will get all ten
single-digit numbers coming up, as you observed. If it does repeat
itself, then you won't get them all.
hat is special about numbers that are in the 2 or 5 times tables
(we call them multiples of 2 or 5)? Imagine you have a
number that is a multiple of five. When you work out its times
table, you multiply it by 1,2,etc. But a multiple of 5 multiplied
by 2 is a multiple of ten, so the pattern repeats as soon as you
multiply your number by 2. In fact you get the pattern 0,5,0,5,0,5
etc. in thelast digit. In the same way, as soon as you get to
multiplying any multiple of 2 by 5, you get a multiple of ten and
you get the pattern 0,2,4,6,8,0,2,4,6,8 etc. However, with numbers
that aren't multiples of 2 and 5 you can only get a multiple of ten
by multiplying by ten, so the pattern will only repeat after ten
entries.
Simon