Hi everybody!!! My name is Isabelle, I'm 10 and am in Year 7 in
Australia. I'm in a gifted and talented maths class at school. We
were given this very hard problem and we're supposed to try to find
a formula and answer. THE MIND BOGGLES!!
The problem is - Tom was floating down the river on a raft when, 1
km lower down, Michael took to the water in a rowing boat. Michael
rowed downstream at the best pace of which he was capable. Then he
turned around and rowed back again and arrived at his starting
point just as Tom drifted by. If Michael's rowing speed in still
water is ten times the speed of the current in the river, what
distance had Michael covered before he turned his boat
around.
Please help me - thanks!!!!
ISABELLE
Suppose the speed of the current is c, and the distance Michael
covers before turning round is D.
Michael travels downstream distance D at a speed of 11c and thus
takes time D/(11c)
Upstream, distance D is covered at a speed of 9c and thus takes
time D/(9c)
This gives a total time of (1/11 + 1/9)*D/(c).
Also Tom travels at speed c and covers 1km so
d = s×t
1 = c×(1/11 + 1/9)×D/(c)
= (1/11 + 1/9)×D
Giving D = 4.95km.