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## 'Egyptian Rope' printed from http://nrich.maths.org/

Randley School sent in four good
solutions.

Naziya said:

I found out that I could make a square with three sections at each
side. I also found out that I could make three different triangles:
an isoscelos triangle $2$ along the bottom and $5$ up each side, a
right angled which had $3$ along the bottom, $4$ up one side and
$5$ on the other side and an equilateral with all three sides the
same. I could also make two different rectangles, like this: $5, 1,
5, 1$ or $4, 2, 4, 2$.

Matthew and Jordan said:

I made three lots of triangles and I made an isosceles triangle
with $2, 5$ and $5$. Then I made an equilateral triangle with three
lots of $4$. The last triangle was a right angled triangle with $5,
4$ and $3$. I made two rectangles one had $4, 2, 4, 2$. The last
rectangle had $5, 1, 5, 1$. The square had $3, 3, 3, 3$. Then we
made a hexagon and it had $2, 2, 2, 2, 2, 2$.

Ffion said:

I made a square with three sections at each side. I made two
rectangles one of them was $5$ across and $2$ down, the second one
was $4$ across and $2$ down. I made three triangles: a right angled
triangle which has $3$ across, $4$ up one side and $5$ on the other
side, the isosceles triangle which has $2$ across and $5$ up, the
other triangle was the equilateral triangle with all the sides had
$4$. I made a hexagon which has $12$ sides.

I'm sure there'll be some rethinking of that
last bit - do you know the name of a $12$-sided shape?

Well done everyone.