Weekly Problem 12 - 2013

Stage: 3 Challenge Level: Challenge Level:1
Let the number be $x$. Then $x^2= 2x^3$, that is $x^2(1-2x)=0$.
So $x=0$ or $x=\frac{1}{2}$.
However, $x$ is positive, so the only solution is $x=\frac{1}{2}$.

This problem is taken from the UKMT Mathematical Challenges.

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