### Golden Thoughts

Rectangle PQRS has X and Y on the edges. Triangles PQY, YRX and XSP have equal areas. Prove X and Y divide the sides of PQRS in the golden ratio.

A 1 metre cube has one face on the ground and one face against a wall. A 4 metre ladder leans against the wall and just touches the cube. How high is the top of the ladder above the ground?

### Days and Dates

Investigate how you can work out what day of the week your birthday will be on next year, and the year after...

# Indigo Interior

##### Stage: 4 Short Challenge Level:
Let the centre of the circle be $O$ and let $A$ and $B$ be corners of one of the shaded squares, as shown.

As the circle has area $\pi$ square units, its radius is $1$ unit. So $OB$ is $1$ unit long.

Let the length of the side of each of the shaded squares be $x$ units.
By Pythagoras's Theorem, $OB^2 = OA^2 + AB^2$, that is $1^2 = (2x)^2 + x^2$.
So $5x^2=1$. Now the total shaded area is $8x^2 = 8 \times \frac{1}{5} = 1 \frac{3}{5}$ square units.

This problem is taken from the UKMT Mathematical Challenges.
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