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Diggits

Can you find what the last two digits of the number $4^{1999}$ are?

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Like Powers

Investigate $1^n + 19^n + 20^n + 51^n + 57^n + 80^n + 82^n $ and $2^n + 12^n + 31^n + 40^n + 69^n + 71^n + 85^n$ for different values of n.

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Two Many

What is the least square number which commences with six two's?

Largest Number

Stage: 3 Challenge Level: Challenge Level:1

Here are the largest solutions that were sent in.

Matthew from South Farnham School:


4096, by doing 4 to the power 3 to the power 2, which is (4 x 4 x 4) x (4 x 4 x 4) = 64 x 64 = 4096.

Josh from Alameda School:


1 048 576, which is 32 to the power of 4 (32 x 32 x 32 x 32).

Greenford School, Dorset sent in 8 796 093 022 208, which is 2 to the power of 43.

Charlotte, Agnes, Susannah and Miranda from Headington Junior School offered 109 418 000 000 000 000 000, which is about 3 to the power 42.

In fact the exact value of 342 is 109 418 989 131 512 359 209 can you say it aloud easily?